materi pti.a

Tugas Mata Kuliah ‘Pengantar Teknik Informasi A’

Konversi bilangan berikut :

 

1.      198010 ke bilangan binear,heksadesimal,dan oktal

2.      10010011012 ke heksadesimal, oktal, dan desimal

3.      768 ke bilangan binear, heksadesimal, dan desimal

4.      43 F 16 ke bilangan binear, desimal, dan oktal

 

Jawaban :

 

Soal no 1

  1. binear: 1980  /2 = 0

990   /2 = 0

495   /2 = 1

247   /2 = 1

123   /2 = 1

61     /2 = 1

30     /2 = 0

15     /2 = 1

7       /2 = 1

3       /2 = 1

1       /2 > 1

binear : 11110111100

  1. heksadesimal : 0111 1011 1100

7                      B                      C

  1. oktal : 011 110 111 100

3                         6                      7                      4

 

Soal no 2

a.       heksadesimal : 0010 0100 1101

2                         4                         D

b.   oktal : 001 001 001 101

1                      1                      1                      5

c.   desimal : 20+22+23+26+29 = 589

 

Soal no 3

oktal : 111 110

7                6

a.   binear : 111110

b.   heksadesimal : 0011 1110

3                      E

c.   desimal : 21+22+23+24+25 = 62

 

Soal no 4

a.   0100 0011 1111

4                   3                      F

binear : 010000111111

b.   oktal : 010 000 111 111

2                   0                7                7

c.   desimal : 20+21+22+23+24+25+26+211 = 2175

 

 

NPM   : 26110488

Nama  : Setyo Aji Pamungkas

Kelas   : 1kb01

Tugas  : Pengantar Teknik Informasi A ’Konversi Bilangan’

 

By setyoaji13

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